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31 January, 22:54

Solve the triangle. Round lengths to the nearest tenth and angle measures to the nearest degree. B = 15° C = 113° b = 49

A. A = 50°, a = 176.3, c = 151.2

B. A = 52°, a = 149.2, c = 174.3

C. A = 52°, a = 151.2, c = 176.3

D. A = 50°, a = 174.3, c = 149.2

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Answers (1)
  1. 31 January, 23:55
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    So, Given that you have A = 23 degrees, B = 21 degrees,

    and side a = 42.8, we find the angle C and the remaining sides of the triangle to be as follows:

    Calculating for C = 180 degrees - (A + B).

    C = 180 - 44 = 136

    a / sin A = b / sin B = c / sin C

    b = a sin B / sin A = 42.8 sin 21 / sin 23 = 39.3

    c = a sin C / sin A = 42.8 sin 136 / sin 23 = 76.1

    42.8/sin 23 = 109.5

    39.3/sin 21 = 109.7

    76.1/sin 136 = 109.6

    The correct answer is (c). C = 136, b = 39.3, and c = 76.1.
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