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7 December, 17:39

For the quadratic equation x2 + 2x + 8 = 0, find the value of the discriminant. Then, describe the number and type of roots for the equation. Finally, find the exact solution of the equation by using the Quadratic Formula.

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  1. 7 December, 17:44
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    ax^2 + bx+c=0

    X^2 + 2x+8=0 so a=1, b=2, c=8

    Discriminat = b^2 - 4ac=2^2 - 4•1•8=4-32=-28

    So there are no real number solutions, yet there are complex numbers solutions.

    Solutions = (-b + - sqrt (discriminant)) / 2•a

    = (-2+-i sqrt (2•2•7)) / 2

    Solutia 1 = - 1 + i sqrt7

    Solutia 2 = - 1 - i sqrt 7
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