A machine shop has an order for 300 solid steel parts to be used on a series of pipeline valve systems. Each part has a volume of 900 cubic centimeters. The cost of the steel is $0.37 per kilogram. The density of the steel is 8.15g / cm^3. What is the cost of the steel for the 300 solid steel parts to the nearest whole dollar

Question

Zander Odonnell

Mathematics

20 January, 21:02

A machine shop has an order for 300 solid steel parts to be used on a series of pipeline valve systems. Each part has a volume of 900 cubic centimeters. The cost of the steel is $0.37 per kilogram. The density of the steel is 8.15g / cm^3. What is the cost of the steel for the 300 solid steel parts to the nearest whole dollar

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Answers (1)

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Rohan Reed · Answer 1

900 cm^3 * 8.15 g / cm^3 = 7335 g for each part

7335 g * 1 kg/1000 g = 7.335 kg

each part weighs 7.335 kgs

they are buying 300 parts

300 * 7.335 kg = 2200.5 kg for the 300 parts

It cost $.37 per kg

2200.5 kg * $.37 per kg = $814.185 for the 300 parts

To the nearest dollar

$814