suppose the area of a square is x^2-10+25. What is the perimeter of the square? Hint * Find the length of the square first.

4x - 20

Step-by-step explanation:

The side length of the square is the square root of the area, so is ...

s^2 = (x^2 - 10x + 25) = (x - 5) ^2

s = (x - 5)

Then the perimeter of the square is 4 times the side length:

P = 4 (x - 5)

P = 4x - 20