Question 1: Which expression correctly shows 2x^5-54x^2 factored over the integers using the difference of cubes method?

a. (x-3) (x^2+3x+9)

b. x^2 (2x-54) (4x^2+54x+2916)

c. 2x^2 (x-3) (x^2+3x+9)

d. The polynomial cannot be factored over the integers using the difference of cubes method.

2 (x-54) (x^2-54x+2916)

Question 2: Which of the following expressions are factors of p (x) = 4x^6+32x^3?

There may be more than one correct answer. Select all correct answers.

1. 4x^3

2. x+2

3. x+8

4. x^3+4

5. x^2-2x+4

6. x^2+2x+4

Question

Ross Benitez

Mathematics

28 April, 08:17

Question 1: Which expression correctly shows 2x^5-54x^2 factored over the integers using the difference of cubes method?

a. (x-3) (x^2+3x+9)

b. x^2 (2x-54) (4x^2+54x+2916)

c. 2x^2 (x-3) (x^2+3x+9)

d. The polynomial cannot be factored over the integers using the difference of cubes method.

2 (x-54) (x^2-54x+2916)

Question 2: Which of the following expressions are factors of p (x) = 4x^6+32x^3?

There may be more than one correct answer. Select all correct answers.

1. 4x^3

2. x+2

3. x+8

4. x^3+4

5. x^2-2x+4

6. x^2+2x+4

+2

Answers (1)

Know the Answer?

Helen Rice · Answer 1

Question 1: Option C, 2x^2 (x - 3) (x^2 + 3x + 9)

Question 2: Options 1, 2, 5

Step-by-step explanation:

Question #3

Step 1: Factor

2x^5 - 54x^2

2x^2 (x^3 - 27)

2x^2 (x - 3) (x^2 + 3x + 9)

Answer: Option C, 2x^2 (x - 3) (x^2 + 3x + 9)

Question #2

p (x) = 4x^6 + 32x^3

Step 1: Factor

4x^6 + 32x^3

4x^3 (x^3 + 8)

4x^3 (x + 2) (x^2 - 2x + 4)

Answer: Options 1, 2, 5