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The length of a rectangle is 3 yd longer than its width. if the perimeter of the rectangle is 50 yd, find its length and width.

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  1. Today, 09:03
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    Length = w+3

    P = 2L + 2W

    50 = 2 (w+3) + 2w

    50 = 2w + 6 + 2w

    50 = 4w + 6

    50-6 = 4w-6

    44 = 4w

    44/4 = 4w/4

    w = 11

    l = 11+3

    l = 14

    50 = 2L+2W

    50 = 2 (14) + 2 (11)

    50 = 28 + 22

    50=50
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