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23 February, 15:26

Y is inversely proportional to x squared. given that y = 2.5 when x = 24.

1. find an expression for y in terms of x y

2. find the value of y when x=20

3. find the value of x when y=16

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Answers (1)
  1. 23 February, 15:49
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    If y is inversely proportional to x^2 ...

    y=k/x^2, we are given that y=2.5 and x=24 so

    2.5=k/24^2

    k=2.5 (24^2)

    k=1440 so

    y=1440/x^2

    y (20) = 1440/400=3.6 so y=3.6 when x=20

    x^2=1440/y

    x^2=1440/16

    x^2=90

    x=±√90

    x=±3√10

    approx ...

    x=-9.49 and + 9.49 so there are two possible values for x when y=16
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