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5 May, 07:36

Find three consecutive even integers such that the sum of the smallest integer and twice the median integer is 20 more than the larger integer

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Answers (2)
  1. 5 May, 07:42
    0
    X=10

    x + 2 = 10 + 2 = 12

    x + 4 = 10 + 4 = 14
  2. 5 May, 07:58
    0
    3 consecutive even integers ... x, x + 2, x + 4

    x + 2 (x + 2) - (x + 4) = 20

    x + 2x + 4 - x - 4 = 20

    2x = 20

    x = 20/2

    x = 10 <==

    x + 2 = 10 + 2 = 12 <==

    x + 4 = 10 + 4 = 14 <==
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