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Nikolai Garrison
Mathematics
25 October, 10:53
Find the solutions
x^2=16x-28
+3
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Clark Mcgee
25 October, 11:17
0
Minus 16x both sides and add 28 to both sides
x^2-16x+28=0
factor
hmm, what 2 numbers multiply to 28 and add to - 16
hmm
1 and 28? nope
2 and 14? yep
since middle term is negative and last tem is positive, both of the factors are negative
(x-14) (x-2) = 0
set each to zero
x-14=0
x=14
x-2=0
x=2
x=2 and 14
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