Mr. Lee asks a student to solve the following system of linear equations. {-28=-40q-14p 10q+4=2p Which ordered pair (p, q) is a solution to the system? (-7/5,-2) (-2,-7/5) (0, 2) (2, 0)

p = 2, q = 0

Step-by-step explanation:

Solve the following system:

{-28 = - 14 p - 40 q | (equation 1)

10 q + 4 = 2 p | (equation 2)

Express the system in standard form:

{14 p + 40 q = 28 | (equation 1)

- (2 p) + 10 q = - 4 | (equation 2)

Add 1/7 * (equation 1) to equation 2:

{14 p + 40 q = 28 | (equation 1)

0 p + (110 q) / 7 = 0 | (equation 2)

Divide equation 1 by 2:

{7 p + 20 q = 14 | (equation 1)

0 p + (110 q) / 7 = 0 | (equation 2)

Multiply equation 2 by 7/110:

{7 p + 20 q = 14 | (equation 1)

0 p+q = 0 | (equation 2)

Subtract 20 * (equation 2) from equation 1:

{7 p+0 q = 14 | (equation 1)

0 p+q = 0 | (equation 2)

Divide equation 1 by 7:

{p+0 q = 2 | (equation 1)

0 p+q = 0 | (equation 2)

Collect results:

Answer: {p = 2, q = 0