Ask Question
6 March, 01:55

What number am i: when you divide me by five the remainder is four, i have to digits both digits are odd, the sum of my digits is 10?

+2
Answers (1)
  1. 6 March, 02:19
    0
    X is the number

    x/5=5a+4

    2 digits that are odd

    sum is 10

    ah, we can make a bit of stuff with the last 2 hints

    sum is 10 and are odd

    that is

    9 and 1

    3 and 7

    5 and 5

    so our possible numbers are

    91,19,37,73,55

    but 55 is divsible by 5 so it is out

    91,19,37,73

    test each

    91/5 has remainder 1

    19/5 has remainder 4

    37/5 has remainder 2

    73/5 has remainder 3

    the number is 19
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “What number am i: when you divide me by five the remainder is four, i have to digits both digits are odd, the sum of my digits is 10? ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers