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30 November, 16:44

Solve the equation using propertis of logarithms and exponents.

9^6x=3^2x+4

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  1. 30 November, 17:13
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    9^ (6x) = 3^ (2x+4) I assume this is what you meant ...

    since 9=3^2

    3^2^ (6x) = 3^ (2x+4)

    and since (a^b) ^c=a^ (bc)

    3^ (12x) = 3^ (2x+4)

    so if a^b=a^c then b=c so

    12x=2x+4

    10x=4

    x=0.4
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