Sin (2x) - 3cos x = 0

Answer:sin (inverse) (3/2)

Step-by-step explanation:

sin (2x) - 3cosx=0 sin2x=2sinxcosx

2sinxcosx-3cosx=0

2sinxcosx=3cosx

Divide both sides by cosx

2sinxcosx ➗ cosx = 3cosx ➗ cosx

2sinx=3

Divide both sides by 2

2sinx ➗ 2=3 ➗ 2

sinx=3/2

x=sin (inverse) (3/2)

2π3, (4π3)