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15 December, 01:41

Suppose that y varies directly as the square of x, and that y=567 when x=9. What is y when x=4

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  1. 15 December, 02:03
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    y = 112

    Step-by-step explanation:

    If y varies directly as the square of x

    mathematically;

    y ∝ x²

    y = kx² where 'k' is the constant of proportionality

    let u know the value of k for this equation by making k the subject of the formular from y = kx²

    divide both sides by x²

    k = y / x²

    given that y = 567 x = 9

    k = 567 / (9) ²

    k = 567/81

    k = 7

    now to get the value of y when x = 4

    from the equation conneting x, y,

    y = kx²

    y = 7 * (4) ²

    y = 7 * 16

    y = 112
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