12 people sit in a row in random order. two of the people are a and

b. what is the probability that a and b sit next to each other g

Question

Jordyn Atkinson

Mathematics

18 October, 01:04

12 people sit in a row in random order. two of the people are a and

b. what is the probability that a and b sit next to each other g

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Triston Davidson · Answer 1

A has a 2 in 12 chance of being at an end and a 10 in 12 chance of being somewhere in the middle. For the end seats, B has a 1 in 11 chance of sitting next to A, and a 2 in 11 chance of being next to A if A's in a non-end seat. (2/12) * (1/11) + (10/12) * (2/11) = 2/132+20/132=22/132 chance of being next to each other.

12 people sit in a row in random order. two of the people are a andb. what is the probability that a and b sit next to each other g

12 people sit in a row in random order. two of the people are a and

b. what is the probability that a and b sit next to each other g