Howard will select two pieces of candy from a bowl with 5 chocolate candies, 4 gummy candies and 6 hard candies. What is Howard's probability of choosing a chocolate candy, eating it, then choosing a gummy candy?

Question

Jakobe Davidson

Mathematics

11 December, 03:57

Howard will select two pieces of candy from a bowl with 5 chocolate candies, 4 gummy candies and 6 hard candies. What is Howard's probability of choosing a chocolate candy, eating it, then choosing a gummy candy?

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Answers (1)

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Chaz Rowland · Answer 1

9.5%.

Step-by-step explanation:

The probability in this case is calculated by publishing the probability of each event. That is, the first event of taking out one of chocolate and then taking out a gummy one where there is one less chocolate.

Therefore, in total they are 5 + 4 + 6 = 15 sweets.

Therefore the probability of getting one of chocolate is:

5/15 = 1/3

Now, in the second event there is one less sweet, that is, 14. Therefore the probability of taking out a gummy one is:

4/14 = 2/7

Then the final probability would be:

(1/3) * (2/7) = 0.095 = 9.5%

The probability of what the statement says is 9.5%.