Drag the tiles to the boxes to form correct pairs. Not all tiles will be used. A car repair center services 920 cars in 2012. The number of cars serviced increases quarterly at a rate of 12% per year after 2012. Create an exponential expression to model the number of cars serviced after t years. Then, match each part of the exponential expression to what it represents in the context of the situation. 920 (1.03) is the number of cars multiplied by 1.03. The quarterly rate of growth is 0.03 or 3%. The compound periods multiplied by the number of years is 4t. The initial number of cars serviced is 920. The growth factor is represented by 1.03. The growth rate is 1.03. Exponent arrowRight Base arrowRight Coefficient arrowRight Rate arrowRight

N = 920 (1+0.03) ^4t

Step-by-step explanation:

According to the given statement a car repair center services 920 cars in 2012. The number of cars serviced increases quarterly at a rate of 12% per year after 2012.

Rate is 12 % annually

rate in quarterly = 12/4 = 3%

We will apply the compound interest equation:

N=P (1+r/n) ^nt

N = ending number of cars serviced.

P = the number of cars serviced in 2012,

r = interest rate

n = the number of compoundings per year

t = total number of years.

Number of compoundings for t years = n*t = 4t

Initial number of cars serviced=920

The quarterly rate of growth = n=4

r = 3%

The growth rate = 1.03

Compound period multiplied by number of years = 920 (1.03) ^4t

Thus N = 920 (1+0.03) ^4t

N = number of cars serviced after t years ...