The half-life of sodium-22 is 2.6 years. A sample contains 800 mg of this isotope.

Which expression represents the mass of sodium remaining after h half-lives?

A. S = 0.5 (800) ^h

B. S = 800^ (0.5) h

C. S = 800^0.5h

D. S = 800^h + 0.5

Question

Clay Dillon

Mathematics

22 March, 06:53

The half-life of sodium-22 is 2.6 years. A sample contains 800 mg of this isotope.

Which expression represents the mass of sodium remaining after h half-lives?

A. S = 0.5 (800) ^h

B. S = 800^ (0.5) h

C. S = 800^0.5h

D. S = 800^h + 0.5

+3

Answers (1)

Know the Answer?

Justice Winters · Answer 1

The half life formula is given by:

N (t) = N (1/2) ^h

where:

N (t) = S=final amount

N=initial amount=800 mg

h=half lives

thus substituting our values we obtain

S=800 (0.5) ^h

The answer is C]

The half-life of sodium-22 is 2.6 years. A sample contains 800 mg of this isotope.Which expression represents the mass of sodium remaining after h half-lives?A. S = 0.5 (800) ^hB. S = 800^ (0.5) hC. S = 800^0.5hD. S = 800^h + 0.5

The half-life of sodium-22 is 2.6 years. A sample contains 800 mg of this isotope.

Which expression represents the mass of sodium remaining after h half-lives?

A. S = 0.5 (800) ^h

B. S = 800^ (0.5) h

C. S = 800^0.5h

D. S = 800^h + 0.5