How do i solve 5-8:4*2-1 using order of operations

First, you multiply and divide everything in order from left to right. Meaning you actually get 5 - ((8/4) * 2) - 1 (If you first multiply with 2 and divide by 4 you'll get the same result (8*2/4=8/4*2). Then the only thing left to do is subtract so 5-4-1 = 0

First;

5-8 : 4x2-1, put parenthesis around the multiplication like so; 5-8 : (4x2) - 1

Solve the problem in the parenthesis; 4x2=8 so; 5-8 : (8) - 1

Then put parenthesis around the division; 5 - (8 : (8)) - 1

Solve the problem within the parenthesis; (8 : (8)) = 1

The problem should look like this now 5-1-1

Now subtract; 5-1=4-1=3

Your answer is 3.

Let me know if I did this wrong or if you have any questions.