The height of a projectile in the air t seconds after it is shot can be modeled by the function y = - 16t^2 + 3200t + 2, where t and y are measured in feet. What is the maximum height that the projectile reaches?

160002 feet

Step-by-step explanation:

y (t) = -16t^2+3200t+2

We need y' to find a maximum

y' (t) = -32t+3200

y' (t) = 0 if t=100

Notes that y' (t) >0 if t100 y' (t) <0. Now we can conclude that y (t) has maximum in t=100

Y (100) = -16*10000+3200*100+2

Y (100) = 160002 feet