If the domain of the function

f (x) = 2x^2-8 is (-2,3,5) then the range is

The range: {0, 10, 42}

Step-by-step explanation:

Put the values of x from the domain to the equation of the function

f (x) = 2x² - 8

for x = - 2

f (-2) = 2 (-2) ² - 8 = 2 (4) - 8 = 8 - 8 = 0

for x = 3

f (3) = 2 (3) ² - 8 = 2 (9) - 8 = 18 - 8 = 10

for x = 5

f (5) = 2 (5) ² - 8 = 2 (25) - 8 = 50 - 8 = 42