The distance traveled, in meters, of a coin dropped from a tall building is modeled by the equation d (t) = 4.9t^2 where d equals the distance traveled at time t seconds and t equals the time in seconds. what does the average rate of change of d (t) from t = 3 to t = 6 represent? the coin travels an average distance of 44.1 meters from 3 seconds to 6 seconds. the coin falls down with an average speed of 14.7 meters per second from 3 seconds to 6 seconds. the coin falls down with an average speed of 44.1 meters per second from 3 seconds to 6 seconds. the coin travels an average distance of 14.7 meters from 3 seconds to 6 seconds.

Question

Keenan Butler

Mathematics

6 February, 19:28

The distance traveled, in meters, of a coin dropped from a tall building is modeled by the equation d (t) = 4.9t^2 where d equals the distance traveled at time t seconds and t equals the time in seconds. what does the average rate of change of d (t) from t = 3 to t = 6 represent? the coin travels an average distance of 44.1 meters from 3 seconds to 6 seconds. the coin falls down with an average speed of 14.7 meters per second from 3 seconds to 6 seconds. the coin falls down with an average speed of 44.1 meters per second from 3 seconds to 6 seconds. the coin travels an average distance of 14.7 meters from 3 seconds to 6 seconds.

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Ernest Webb · Answer 1

Average rate of change from t = 3 to t = 6 is (d (6) - d (3)) / (6 - 3) = (4.9 (6) ^2 - 4.9 (3) ^2) / 3 = (4.9 (36) - 4.9 (9)) / 3 = (176.4 - 44.1) / 3 = 132.3/3 = 44.1

Therefore, the coin travels an average distance of 44.1 meters from 3 seconds to 6 seconds.