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Alayna Pitts
Mathematics
Today, 10:46
Evaluate - tan²A + 1 + sec²A
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Monique Craig
Today, 11:02
0
Step-by-step explanation: sec^2A-tan^2A+1
=1+1
=2
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Terrance Gonzales
Today, 11:08
0
Hello:
secA = 1/cosA
tanA = sinA / cosA
- tan²A + 1 + sec²A = - (sinA / cosA) ² + 1 + (1/cosA) ²
= - sin²A / cos²A + 1 + 1 / cos²A
= ( - sin²A + cos²A + 1) / cos²A
= (1 - sin²A + cos²A) / cos²A
but : 1 - sin²A = cos²A because : sin²A + cos²A = 1
so : - tan²A + 1 + sec²A = (2 cos²A) / (cos²A)
- tan²A + 1 + sec²A = 2
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