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Let f (x) = 3x^2-8 and let g (x) = 4x+1. Find the given value f[g (-1) ]

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  1. 9 July, 16:14
    0
    19

    Step-by-step explanation:

    given:

    f (x) = 3x²-8

    g (x) = 4x+1

    g (-1) = 4 (-1) + 1

    g (-1) = - 4 + 1

    g (-1) = - 3

    hence

    f[g (-1) ]

    = f (-3)

    = 3 (-3) ²-8

    = 3 (9) - 8

    = 19
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