The probability of picking two black marbles from a box at random without replacement is 10/91.

The probability of drawing a black marble first is 5/14.

What is the probability of picking a second black marble, given that the first marble picked was black?

4/13

85/182

25/637

45/182

Question

Guest

Mathematics

2 January, 11:49

The probability of picking two black marbles from a box at random without replacement is 10/91.

The probability of drawing a black marble first is 5/14.

What is the probability of picking a second black marble, given that the first marble picked was black?

4/13

85/182

25/637

45/182

+4

Answers (1)

Know the Answer?

Dashawn Good · Answer 1

The probability of the 2 events are multiplied to get the result 10/91

so we have the relation 5/14 * x = 10/91

where x is the probability of drawing the second black

so x = 10/91 * 14/5 = 4/13 answer

The probability of picking two black marbles from a box at random without replacement is 10/91.The probability of drawing a black marble first is 5/14.What is the probability of picking a second black marble, given that the first marble picked was black?4/1385/18225/63745/182

The probability of picking two black marbles from a box at random without replacement is 10/91.

The probability of drawing a black marble first is 5/14.

What is the probability of picking a second black marble, given that the first marble picked was black?

4/13

85/182

25/637

45/182