The complex solution to a quadratic equation is x equals start fraction three plus or minus square root of negative 36 end square root over six end fraction full stop Write this solution in standard form, a + bi, where a and b are real numbers. What are the values of a and b?

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Mathematics

2 April, 13:31

The complex solution to a quadratic equation is x equals start fraction three plus or minus square root of negative 36 end square root over six end fraction full stop Write this solution in standard form, a + bi, where a and b are real numbers. What are the values of a and b?

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Sarai Blackburn · Answer 1

The square root of a - 36 simplifies to "6i". So you have 3 + / - [6i/6]. The 6's cancel each other out leaving 3+/-i. So the "a" is 3 and the "b" is 1