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8 June, 17:07

A contractor wishes to build 9 houses, each different in design. In how many ways can he place these houses on a street if 6 lots are on one side of the street and 3 lots are on the opposite side?

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  1. 8 June, 17:12
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    Hello,

    Let's put the 6 houses on side: 6P9=9*8*7*6*5*4/6! = 84

    For each choice there are 3! choices pour the other side

    84*3!=504
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