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29 January, 02:37

Solve the following equation, giving the exact solutions which lie in [0, 2π). (Enter your answers as a comma-separated list.)

sin (2x) = sin (x)

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  1. 29 January, 02:42
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    Sin (2x) = 2sin (x) cos (x) - - > (trigonometric identities)

    2sin (x) cos (x) = sin (x)

    divide by sin (x)

    2cos (x) = 1

    cos (x) = 1/2

    arccos (1/2) = pi/3, 4pi/3
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