Find a polynomial of degree 3 with real coefficients and zeros of - 3,-1, and 4, for which f (- 2) = -18.

Step-by-step explanation:

hello:

f (x) = a (x+3) (x+1) (x-4)

now calculate a if f (-2) = 18 means when x=-2 y=18

so : a (-2+3) (-2+1) (-2-4) = 18

6a=18

a=18/6=3

conclusion : f (x) = 3 (x+3) (x+1) (x-4)