Find the x and y intercepts of the quadratic equation

f (x) = - x^2+4x-4

X - Intercept

f (x) = - x² + 4x - 4

0 = - x² + 4x - 4

x = - (4) + / - √ ((4) ² - 4 (-1) (-4))

2 (-1)

x = - 4 + / - √ (16 - 16)

-2

x = - 4 + / - √ (0)

-2

x = - 4 + / - 0

-2

x = - 4 + 0 x = - 4 - 0

-2 - 2

x = - 4 x = - 4

-2 - 2

x = 2 x = 2

The solution to the problem is {2, 2}, or {2}. The x - intercept of the problem is (2, 0).

Y - Intercept

f (x) = - x² + 4x - 4

f (x) = - (0) ² + 4 (0) - 4

f (x) = - (0) + 0 - 4

f (x) = - 0 + 0 - 4

f (x) = 0 - 4

f (x) = - 4

The y - intercept of the problem is (0, - 4).