If two parrallelograms have the same base length, but the height of the first is half of the second, then what is the ratio of the area if the first parrallelogram to that of the second?

Area of a parallelogram = b * h

Let the heights of first and second parallelogram be h and h' respectively.

Given that,

h = ½h'

Area of first parallelogram = bh ... (i)

Area of second parallelogram = bh'

but, h = ½h'

Replacing h by ½h' in equation (i)

Therefore, area of first parallelogram = ½bh'

Ratio - ½bh' : bh'

= 1:2