The length of the rectangular basketball court is 44 feet more than the width. If the perimeter of the basketball court is 288 feet, what are it's dimensions?

Let's first say that L=W+44

and then remember that perimeter is P=2L+2W

replace the L with W+44

we then get P=2 (W+44) + 2W, now I'll solve it

P=2W+88+2W

P=4W+88

substitute 288 for P

288=4W+88

200=4W

50=W

so now we now how wide the court is. add 44 to find the length which gives you L=94

as always plug the numbers back into your perimeter equation to ensure L and W are correct