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5 August, 15:57

Community sports complex being built in Oak Valley. Perimeter of the rectangular playing field is 542 yards. Length of the field is 9 yards less than quadruple the width. What are the dimensions of the playing field

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  1. 5 August, 16:14
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    Perimeter of field = 542 yards

    Let the width of the field be x.

    As given in the question, length of the field is 9 yards less than quadruple the width.

    So, length = (4x - 9) yards

    We know that perimeter of a rectangle is given as:

    Perimeter = 2 (length + width)

    542 = 2 (x + 4x - 9)

    271 = 5x - 9

    5x = 280

    x = 280 / 5

    x = 56

    Hence, width of field = 56 yards

    Length of field = 4x - 9

    = 4*56 - 9

    = 215 yards
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