What is the solution to the system of equations below? y=-2x-6 and 2y=4x-12

{x = 0, y = - 6

Step-by-step explanation:

Solve the following system:

{y = - 2 x - 6 | (equation 1)

{2 y = 4 x - 12 | (equation 2)

Express the system in standard form:

{2 x + y = - 6 | (equation 1)

{ - (4 x) + 2 y = - 12 | (equation 2)

Swap equation 1 with equation 2:

{ - (4 x) + 2 y = - 12 | (equation 1)

{2 x + y = - 6 | (equation 2)

Add 1/2 * (equation 1) to equation 2:

{ - (4 x) + 2 y = - 12 | (equation 1)

{0 x+2 y = - 12 | (equation 2)

Divide equation 1 by 2:

{ - (2 x) + y = - 6 | (equation 1)

{0 x+2 y = - 12 | (equation 2)

Divide equation 2 by 2:

{ - (2 x) + y = - 6 | (equation 1)

{0 x+y = - 6 | (equation 2)

Subtract equation 2 from equation 1:

{ - (2 x) + 0 y = 0 | (equation 1)

{0 x+y = - 6 | (equation 2)

Divide equation 1 by - 2:

{x+0 y = 0 | (equation 1)

{0 x+y = - 6 | (equation 2)

Collect results:

Answer: {x = 0, y = - 6