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15 December, 07:05

Given that (2x-1) (x+5) = 2x^2-mx-5, what is the value of m

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  1. 15 December, 07:33
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    Expand the left side

    2x (x + 5) - 1 (x + 5) = 2x² - mx - 5

    2x² + 10x - x - 5 = 2x² - mx - 5

    2x² + 9x - 5 = 2x² - mx - 5

    cancel 2x² and - 5

    9x = - mx

    m = - 9

    sorry i was wrong, my mistake hehe
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