Suppose you have two 100 mL graduated cylinders. In each cylinder, there is 40.0 mL of water. You also have two cubes: one is lead, and the other is aluminum. Each cube measures 2.90 cm on each side. After you carefully lower each cube into the water of its own cylinder, what will the new water level be in each of the cylinders?

Question

Blimpie

Mathematics

8 May, 13:51

Suppose you have two 100 mL graduated cylinders. In each cylinder, there is 40.0 mL of water. You also have two cubes: one is lead, and the other is aluminum. Each cube measures 2.90 cm on each side. After you carefully lower each cube into the water of its own cylinder, what will the new water level be in each of the cylinders?

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Marissa Adkins · Answer 1

Answer:64.389

Step-by-step explanationthe new volume in each cylinder will be the volume of water + volume 1 cube (assuming the cubes does not float on water)

then volume of a cube = side^3 = (2.90 cm) ^3 = 24.389cm^3=24.389mL

(considering that 1 ml = 1 cm^3)

Finally the new level of each cylinder is=40 mL+24.389mL=64.389 mL

(if the cube float we need to consider the volume under water (with densities which are not given)