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12 August, 03:58

The sum of the digits of a two-digit number is 11. The number obtained by interchanging the digits exceeds twice the original number by 34. What is the original number?

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  1. 12 August, 04:28
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    Cool problem

    x and y are the digits

    x+y=11

    yx=2 (xy) + 34

    I'm not sure how to solve this using legit math so use trial and error

    the 1 digit numbers that could be possible are

    9,2

    8,3

    7,4

    6,5

    5,6

    4,7

    3,8

    2,9

    all of them add up to 11

    the pairs obtained by swiching the number are

    92 and 29

    83 and 38

    74 and 47

    65 and 56

    we find which ones are equal when we subtract 34 from the larger number and divide by 2

    92-34=58

    58/2=29

    92 and 29 work

    83-34=49

    49/2=24.5 not equal to 38 not work

    74-34=40

    40/2=20 47 not equal to 20 so doesn't work

    65-34=31

    31/2=15.5 not equal to 56 so doesn't work

    the origonal number is 29
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