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Kash Wilson
Mathematics
15 March, 19:49
Find the set the solves
+2
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1
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Gilbert Chavez
15 March, 19:51
0
Hello,
To exist x≠0
if x>0 then
x+2/x>=3==>x²+2>=3x
==>x²-3x+2>=0
==> (x-2) (x-1) >=0 positive out of the roots
==> (x=2) and x>0
==> (0
else
x<0
x+2/x>=3==>x²+2<=3x
==>x²-3x+2<=0 negative betheen the roots
==> (1<=x<=2) and x<0 : no solution
end if
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