Ask Question
3 January, 16:23

Steven has 14 steel balls of equal weight. If he puts 9 of them in one pan of a pan balance and the rest along with a weight of 20 grams in the other pan, the pans balance each other. What is the weight of one steel ball? A) 5 grams B) 14 grams C) 20 grams D) 0.65 grams

+4
Answers (2)
  1. 3 January, 16:27
    0
    Option A - 5 grams

    Step-by-step explanation:

    9 balls in one side

    = 5 balls other side with 20 gram

    5 + 4 balls one side

    = 5 + 20 grams other side

    5 + 4 balls

    = 5 balls + 20/4

    5 gm of I ball weight 9 * 5 = 45

    5 * 5 + 20

    = 45
  2. 3 January, 16:51
    0
    b = 5 grams

    Step-by-step explanation:

    Let b represent the weight of one ball.

    Then 9b = 20 grams + 5b.

    Solving for b, subtract 5b from both sides, obtaining 4b = 20 grams.

    Then b = the weight of one steel ball = 5 grams.

    Check: Does 9 (5 grams) = 20 grams + 5 (5 grams) ?

    Does 45 grams = 45 grams? YES
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Steven has 14 steel balls of equal weight. If he puts 9 of them in one pan of a pan balance and the rest along with a weight of 20 grams in ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers