On top of a hill, a rocket is launched from a distance 80 feet above a lake. The rocket will fall into the lake after its engine burns out. The rocket's height, h, in feet above the surface of the lake, is given by the equation, h = - 16t 2 + 64t + 80, where t is time in seconds. The maximum height of the rocket is a0 feet. trying to find the max height of the rocket

Question

Juan Bass

Mathematics

17 January, 15:29

On top of a hill, a rocket is launched from a distance 80 feet above a lake. The rocket will fall into the lake after its engine burns out. The rocket's height, h, in feet above the surface of the lake, is given by the equation, h = - 16t 2 + 64t + 80, where t is time in seconds. The maximum height of the rocket is a0 feet. trying to find the max height of the rocket

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Hailie Riley · Answer 1

On top of a hill, a rocket is launched from a distance 80 feet above a lake. The rocket will fall into the lake after its engine burns out. The rocket's height, h, in feet above the surface of the lake, is given by the equation, h = - 16t 2 + 64t + 80, where t is time in seconds