V (t) = 2000e^-.35t At what rate's compute value falling after 3 years

Given the value of computer at t years

V (t) = 2000e^-.35t

The rate of the computer value falling is given by:

dv (t) / dt = 2000 x 0.35e^-0.25t = - 700e^-0.35t

at t = 3years,

dv (t) / dt|t=3 = - 700e^-0.35x3 = - 245

The computer value falls at a rate of 245 after 3 years.