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17 September, 00:47

write an equation in slop-intercept form for a line that is perpendicular to the line y = - 5x-3 and has a y-intercept of 6.

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  1. 17 September, 01:09
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    The equation of the line would be y = 1/5x + 6

    Step-by-step explanation:

    First, to find the slope of a perpendicular line, you need to find the opposite and reciprocal of the original slope. Since the original is - 5, we first change the sign (which makes it just 5). Now we take that 5 and flip it to get 1/5.

    Now that we have the slope as 1/5, we can use that and the intercept in slope-intercept form to get the equation.

    y = mx + b

    y = 1/5x + 6
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