Which expression is equivalent to sin (1.8x) sin (0.5x) ?

Question

Gia Chaney

Mathematics

5 January, 23:41

Which expression is equivalent to sin (1.8x) sin (0.5x) ?

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Nolan · Answer 1

Hum, this problem was difficult. You use the next expression to solve this problem. / [/cos (A - B) = / cos A / cos B + / sin A / sin B / ] / [/cos (A + B) = / cos A / cos B - / sin A / sin B/] / [/cos (A - B) - / cos (A + B) = 2 / sin A / sin B/] So / [/sin A / sin B = 0.5 / left (/cos (A - B) - / cos (A + B) / right) / ] A = 1.8 x, B = 0.5 x / [/sin (1.8x) / sin (0.5x) = 0.5/left (/cos (1.8-0.5) x - / cos (1.8+0.5) x / right) / ]/[ = 0.5 / left (/cos (1.3x) - / cos (2.3x) / right) / ] It's finish!