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Andy Bonilla
Mathematics
15 May, 02:34
Hence solve the equation x^3+x^2-6x=0
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Marisol Davila
15 May, 02:50
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x³ + x² - 6x = 0
x (x² + x - 6) = 0
x (x² + 3x - 2x - 6) = 0
x[x (x + 3) - 2 (x + 3) ] = 0
x (x - 2) (x + 3) = 0
x₁ = 0
x - 2 = 0 = > x₂ = 2
x + 3 = 0 = > x₃ = - 3
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Jordon Webb
15 May, 02:57
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Answer:x³ + x² - 6x = 0
x (x² + x - 6) = 0
x (x² + 3x - 2x - 6) = 0
x[x (x + 3) - 2 (x + 3) ] = 0
x (x - 2) (x + 3) = 0
x₁ = 0
x - 2 = 0 = > x₂ = 2
x + 3 = 0 = > x₃ = - 3
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