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15 May, 02:34

Hence solve the equation x^3+x^2-6x=0

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Answers (2)
  1. 15 May, 02:50
    0
    x³ + x² - 6x = 0

    x (x² + x - 6) = 0

    x (x² + 3x - 2x - 6) = 0

    x[x (x + 3) - 2 (x + 3) ] = 0

    x (x - 2) (x + 3) = 0

    x₁ = 0

    x - 2 = 0 = > x₂ = 2

    x + 3 = 0 = > x₃ = - 3
  2. 15 May, 02:57
    0
    Answer:x³ + x² - 6x = 0

    x (x² + x - 6) = 0

    x (x² + 3x - 2x - 6) = 0

    x[x (x + 3) - 2 (x + 3) ] = 0

    x (x - 2) (x + 3) = 0

    x₁ = 0

    x - 2 = 0 = > x₂ = 2

    x + 3 = 0 = > x₃ = - 3
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