Find the solution to the equation below. 2x^2+3x-20=0

A. x = - 4, - 3/2

B. x = - 4, 3/2

C. x = - 5/2, 4

D. x = - 4, 5/2

The right choice is (D) x = - 4, 5/2

Step-by-step explanation:

2x^2+3x-20=0

By factoring the expression we get

2x²2 + 8x-5x-20=0

(x+4) (2x-5) = 0

Now

(x+4) = 0 OR x = - 4

and

(2x-5) = 0 OR x = 5/2

S the solutions are

x = - 4 and x = 5/2

C maybe bro I'm not really sure tho think I'm messing up