What is y = (x-6) ^2 - 2 in y = ax^2+bx+c form

Question

Jacey Evans

Mathematics

11 November, 03:14

What is y = (x-6) ^2 - 2 in y = ax^2+bx+c form

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Answers (2)

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Beckett Velez · Answer 1

Easy, just expand

y = (x-6) ^2-2

y = (x-6) (x-6) - 2

y=x^2-6x-6x+36-2

y=x^2-12x+34

y=ax^2+bx+c

a=1

b=-12

c=34

Wizard · Answer 2

Y = (x - 6) ² - 2

y = (x - 6) (x - 6) - 2

y = (x (x - 6) - 6 (x - 6)) - 2

y = (x (x) - x (6) - 6 (x) + 6 (6)) - 2

y = (x² - 6x - 6x + 36) - 2

y = (x² - 12x + 36) - 2

y = x² - 12x + 36 - 2

y = x² - 12x + 34