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13 November, 02:35

Use substitution to solve each system of equations

c-5d=2

2c+d=4

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Answers (2)
  1. 13 November, 02:50
    0
    2x-y = - 4 OR y = 2x+4

    -3x+y=44

    -3x + (2x+4) = 44

    -x = 40

    x = - 40 and y = - 76 (2*-40 + 4)

    c-5d=2 OR c = 5d + 2

    2c + d = 4

    2 (5d+2) + d = 4

    11d = 0

    d = 0 and c = 2
  2. 13 November, 02:52
    0
    2x-y = - 4 OR y = 2x+4

    -3x+y=44

    -3x + (2x+4) = 44

    -x = 40

    x = - 40 and y = - 76 (2*-40 + 4)

    c-5d=2 OR c = 5d + 2

    2c + d = 4

    2 (5d+2) + d = 4

    11d = 0

    d = 0 and c = 2
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