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7 July, 04:09

Find four consecutive integers such that three times the sum of the first and the fourth is 114 less than the product of - 5 in the sum of the first two consecutive integers what are the integers?

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  1. 7 July, 04:34
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    3 (x + (x + 3)) + 114 = - 5 (x + (x + 1))

    6x + 18 + 114 = - 10x - 5

    16x = - 137

    That's what I get.
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