My sister was fooling around wi her money the other night and left the coins in a pattern of four rows with four coins in each row. Each row had exactly one penny, one nickel, one dime, and one quater

one penny = S

one nickel = T

one dime = U

one quater = V

∴ Probability one obtaining at least one of S, T, U or V = 4/24 = 1/6

Step-by-step explanation: They can be arranged as follows

1) STUV

2) TSUV

3) TSVU

4) UVST

5) VUST

6) VUTS

7) TVUS

8) TVSU

9) TUVS

10) SVUT

11) VSTU

12) VSUT

13) SVTU

14) UTSV

15) UTVS

16) USTV

17) USVT

18) VTUS

19) VTSU

20) SUTV

21) SUVT

22) STVU

23) TUSV

24) UVTS