On a coordinate plane, a parabola opens up. It starts in quadrant 1, crosses the x axis where the vertex is in quadrant 4, and crosses the x-axis back into quadrant 1. Which function could be represented by the graph on the coordinate plane? f (x) = (x - 8) 2 + 6 f (x) = (x + 8) 2 + 6 f (x) = (x + 8) 2 - 6 f (x) = (x - 8) 2 - 6

Question

Hanna Richardson

Mathematics

5 December, 11:35

On a coordinate plane, a parabola opens up. It starts in quadrant 1, crosses the x axis where the vertex is in quadrant 4, and crosses the x-axis back into quadrant 1. Which function could be represented by the graph on the coordinate plane? f (x) = (x - 8) 2 + 6 f (x) = (x + 8) 2 + 6 f (x) = (x + 8) 2 - 6 f (x) = (x - 8) 2 - 6

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Answers (2)

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Taryn Decker · Answer 1

The answer for this question is f (x) = (x - 8) 2-6.

Deja Church · Answer 2

F (x) = (x - 8) 2-6

if you simplify the equation you're left with f (x) = (x - 8) - 4. there are two transformations that can be derived from this equation: translate horizontally right 8 and translate vertically down 4. because the parabola starts in quadrant 1, the parabola needs to be translated right opposed to left to match this. since the parabola's vertex is in the negative quadrant 4, the function needs to be moved down which matches the second vertical translation the equation gives us.